Sunday, May 2, 2021

ML AGGARWAL CLASS 8 Chapter 14 Constructions of Quadrilaterals Exercise 14.1

 Exercise 14.1


Question 1


(diagram should be added)


Steps.

1. Draw PQ = 4.5cm

2.From Q draw are of length 6cm

3.From p draw are of length 6.5cm, intersection point is 'R'

4.From R draw are of length 5.5cm

5.From P draw are of the length 5cm , Intersection point is 'S'

6.Join $\overline{\mathrm{Q} R }, \overline{\mathrm{SR}}_{ ,} \overline{\mathrm{PS}}$, required quadrilature PQRS formed



Question 2


(diagram should be added)


Steps.

1. Dract $A B=3.5 \mathrm{Cm}$

2. From 'A' draw Are $A D=5 \mathrm{Cm}$

3.From 'B'  draw Arc BD = 5.4cm , Intersection point is 'D'

4. From $B^{\prime}$ draw Are $B C=5 \mathrm{~cm}$.

5.From 'D' draw arc DC = 5.6 cm , Intersection Point is 'C'

6.Join $\overline{A D}, \overline{D C}, \overline{B C}$ The required quadrilateral ABCD is formed


Question 3


(diagram should be added)


Steps.

1. Draw $P Q=3 \mathrm{~cm}$ line

2.From Q , draw arc QR 2.2cm

3.From P , draw arc PR = 4CM , Intersection Point is 'R'

4.From  Q , draw arc QS = 5CM

5. From P, Draw arc PS = 3.5 CM , Intersection point is 'S'

6.Join $\overline{Q R}$, $\overline{P S}_{,} \overline{S R}$, Now required quadrilateral is formed



Question 4


(diagram should be added)


Steps.

1.Draw $A B=5 \mathrm{~cm}$ line

2.From 'A' draw Ac =7cm

3.From 'B' draw arc BC = 5.5 cm , Intersection point 'C'

4.From 'A' draw Arc AD = 5.5 cm

5. From 'C' draw Arc CD = 4.5 cm , Intersection point 'D'

6. Join $\overline{B C}, \overline{D L}, \overline{A D}$, Now required quadrilateral ABCD fromed.



Question 5


(diagram should be added)

Steps.

1. Draw $B C=6 \mathrm{~cm}$ line

2. At 'C' Draw C= 90 line upto $\overline{DC}=4 \mathrm{~cm}$ nuric point 'D'

3. From 'B' Draw $\angle B=45^{\circ}$ line 

4. From 'D' draw $\angle D=120^{\circ}$ Line , Intersection point is 'C '

5. Join $\overline{B C}, \overline{C D}$ Now required quadrilateral ABCD formed.



Question 6



(diagram should be added)

Steps.

1.Draw PQ = 4cm line 

2. Draw $\angle$ Q = 90 line up $\overline QR$= 6cm and mark 'R'

3.Draw $\angle P 60^{\circ}$ line

4.Draw $\angle$ R=120 line , Intersection Point is 'S'

5. Join $\overline{\mathrm{PS}}, \overline{\mathrm{SR}}$, Now required quadrilateral PQRS formed


  

Question 7



(diagram should be added)

Steps.

1. Draw $A B=5 \mathrm{Cm}$ line

2. Draw $\angle B=60^{\circ}$ line from $B^{\prime}$

3.Draw Cut $\angle B=60^{\circ}$ Line with Arc of BC = 4.2 cm point 'C'

4.At 'A' Draw $\angle A=90$ and at a distance of AD = 3.5cm mark 'D'

5.Join $\overline{D C}$ Now required quadrilateral ABCD is formed.\



Question 8 



(diagram should be added)

Steps.

1. Draw PQ= $4 \mathrm{~cm}$ line

2.Draw $\angle Q=60^{\circ}$ line and at from Q, draw arc of QR = 5cm

3.Draw $\angle R=90^{\circ}$ line upto a distance $R S=$\amgle 4.5 \mathrm{~cm}$

4.Now Join $\overline PS$ Now required quadrilateral PQRS formed.


Question 9


(diagram should be added)

Steps.

1. Draw $B E=3.8 \mathrm{~cm}$ line

2. Draw $\angle E=80^{\circ}$, and an arc $E S=3.4 \mathrm{~cm}$ and both cut at point 's'

3. Draw ST= 4.5 cm arc from 'S'

4. Draw BT = 5cm Arc from 'B' and Intersection Point 'T'

5. Now join $\overline{B C}, \overline{T S}$ required quadrilateral BEST formed.


Question 10


(diagram should be added)

Steps.

1. Draw $A B=4.5 \mathrm{~cm}$ line

2.Draw  $\angle B=60^{\circ}$ line From 'B' and draw an arc BC = 4cm from 'B' Intersection Point is 'C'

3. Draw arc Dc = 3.9 cm From 'C'

4. Draw arc AD =3.2 cm from 'A' Intersection Point 'D'

5.Join $\overline{C D}, \overline{A D}$ , Now required quadrilateral ABCD formed.


 Exercise 14.2


Question 1


(diagram should be added)

Steps.

1. Draw $A B=5 \mathrm{Cm}$

2. Draw $\angle B=120^{\circ}$ line and Cut it ar $\overline{B C}=3.2 \mathrm{Cm}$, merk point ' $c$ '

3.Draw $\angle A=\left(180^{\circ}-120^{\circ}\right)=60^{\circ}$ at Cut it at $\overline{AD}=$ 3.2cm , Mark point 'D'

4.Now join $\overline{D C}$, required qudrilateral $A B C D$ formed.



Question 2


(diagram should be added)

Steps.

1. Draw AB=4.8 $\mathrm{~cm}$ line

2 Draw B C =4cm Arc formed 'B'

3. Draw $A D=B C=4$ im Are form $A$

4.Draw BD = 5.4cm are form B, intersection point 'D'

5.Join $\overline{ AD}$ and draw BC line parallel to AD intersection point is 'C'

6.Join $\overline{D C}, \overline{B C}$ now required quadrilateral is formed.


Question 3



(diagram should be added)

Steps.

1.Draw Bc = 4.5 cm 
 $B O=\frac{1}{2}(B D)=\frac{1}{2}(4)=2 \mathrm{~cm}$

$C O=\frac{1}{2}(A C)=\frac{1}{2}(56)=2.8 \mathrm{Cm}$

$'O^{\prime}$ is formed.

2. Extend Bo Such that $B D=4 \mathrm{~cm}$

3.Extend CO Such that AC= 5.6cm

4. Now required parallelogram ABCD is formed


Question 4



(diagram should be added)

Steps.

1. Draw $A O=\frac{1}{2}(A C)$=3cm and 

produce AO to C such thus OC=OA

2.AO Construct $\angle A O P=45^{\circ}$

3.From OP, cut OB = 2.5cm , produced OB to D such thus OB = OD

4. Join $\overline{A D}, \overline{A B}, D \overline {C}, \overline{C D}$ ABCD parallelogram formed.



Question 5



(diagram should be added)

Steps.

1.Draw AB= 5.6cm

2.Draw $\angle B=90$ and BC = 4cm

3.Draw $\angle A=90$ and AD=BC=4c

4. Join $\overline$ DC , now rectangle ABCD is formed

 

Question 6



(diagram should be added)

Steps.

1. Draw $A B=5 \mathrm{~cm}$

Draw $A O=B O=3.4 \mathrm{~cm}$

2. Extend AO to C such tas $A C=6.8 \mathrm{~cm}$

Extend $B O$ to $D$ Such them $B D=6.8 \mathrm{~cm}$

3. Join $\overline{A D}, \overline{D C}, \overline{B C}$, Now rectangle ABCD is formed.



Question 7


(diagram should be added)

Steps.

1. Draw $A B=4 \mathrm{~cm}$

2. Draw $\angle B A C=90$ \& $\angle B 290^{\circ}$,

3. join $\overline{D C}, A D$, required rectangle $A B C D$ is formes.


Question 8


(diagram should be added)

Steps.

1. $A O=9.3 \mathrm{~cm}$ extend to C

Such that AO = OB

2. $\angle A O B=120^{\circ}$ and DrAW $B O=3.3 \mathrm{~cm}$ and external to D such then BO =OD

3. Join $\overline{A B}, \overline{B C}, \overline{C D}, \overline{A D}$, Now required rectangle ABCD is formed


Question 9


(diagram should be added)

Steps.

1.Draw AB = 5cm

2. At 'A' construct $\angle B A P=45^{\circ}$

3. From AP, cut off AD = 5cm

4.With B as centre and radius 5cm draw an arc 

5.With D as centre and radius 5cm draw are meet radius arc at C

6. Joion BC and CD Then ABCD a required rohmbus

Question 10


(diagram should be added)

Steps.

1. Drau $A B=4.5 \mathrm{~cm}$

2. A as centre ,with 4.5cm radius draw arc

3. B as centre , with 5cm radius draw arc which meet previous arc at 'D'

4. With DC as centre with 4.5cm radius draw arcs they meet at 'C'

5. Join  $\overlineAD, \overline\overline{D C}, \overline{B C}$, then $A B C D$ is required rohmbus

Question 11


(diagram should be added)

Steps

1. Draw $A C=6.8 \mathrm{~cm}$

2. Draw PQ, which perpendicular bisectornof $A C$

3.Cut PQ such then OB= OD =2.6cm

4.Join $\overline{A B}, \quad \overline{B C},\overline{C D}, \overline{A D}$ Now ABCD is required rhombus.


Question 12



(diagram should be added)

Steps.

1. Draw $A B=4.3 \mathrm{Cm}$

2. $\angle A=90^{\circ}$ 'A' as centre, 4.4 cm radius draw arc , both meet at 'D'

3. Repeat the same at 'B' 'C' is Formed

4. Join AD, DC, BC , Now ABCD is required Square.



Question 13


(diagram should be added)

Steps.

1. Draw AC= 6.2 cm

2. Draw PQ , which is perpendicular bisector of AC

3. Cut PQ , from 'O ' Both sides such that OB = OD =3.1cm

4. Join AB,BC,CD, AD , Then ABCD is required square 






































































































































































































































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